Comments on: 2.3 — Variable sizes and the sizeof operator

By: Ascendancy

Ascendancy — Thu, 29 Dec 2011 08:31:16 +0000

As does mine.

By: Integers | 4sharesite

Integers | 4sharesite — Sun, 18 Dec 2011 12:51:25 +0000

[...] is that they have varying sizes — the larger integers can hold bigger numbers. You can use the sizeof operator to determine how large each type is on your [...]

By: jimbo

jimbo — Fri, 09 Dec 2011 00:20:00 +0000

It’s ok I just worked it out. one bit can store two values i.e a 0 or a 1 i.e 2^1 2*1=2. 2 bits can store 4 different values i.e 2^2 2*2= 4 and 3 bits can store 8 different values i.e 2^3 2*2*2= 8.

One more thing..just wondering what to the nth power means? is it like 2^9 or 2*2*2*2*2*2*2*2*2? Many thanks in advance.

By: jimbo

jimbo — Fri, 09 Dec 2011 00:02:11 +0000

First of all thanks Alex for this amazing tutorial…your awesome!!

I was just wandering if one bit can store a 0 or a 1 so two values and two bits can store 4 different values i.e 0101. How come it says 3 bits can store 8 values i.e 01010101? Surely 3 bits would store 6 different values if 1 bit stores 2 different values. 3*2 = 6. If I am missing the point can someone please try and explain where I am going wrong!?
Many thanks in advance.

By: sanjeev_e

sanjeev_e — Tue, 01 Nov 2011 07:27:08 +0000

Hi Alex/Members,

Is there any other way to find the size of a variable without using sizeof(operator).

I have seen in some of the websites that the below way we can find the same.

int i = 1;

size_t size1 = (char*)(&i+1)-(char*)(&i);

size_t size2 = (int*)(&i+1)-(int*)(&i);

cout<

Output: 4 1

Why it is varying here by typecasting with different datatypes?

I want to know where it is restricted to use sizeof() operator anywhere? and also whether the above code internally uses sizeof() operator like

size1 = address-diff/sizeof(int); size2 = address-diff/sizeof(char);

Please clarify.

Thanks,
Sanjeev.

By: Kostas81

Kostas81 — Sun, 07 Aug 2011 21:10:32 +0000

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By: sachinbhanushali

sachinbhanushali — Sun, 26 Jun 2011 10:52:07 +0000

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By: zingmars

zingmars — Wed, 11 May 2011 13:10:41 +0000

It would be easier to explain the whole thing using the architecture name x86(x86_64) rather than calling them ’32-bit’ machines. Confuses people.

By: daksh

daksh — Sun, 16 Jan 2011 14:44:20 +0000

bool: 1 bytes char: 1 bytes wchar_t: 2 bytes short: 2 bytes int: 4 bytes long: 4 bytes float: 4 bytes double: 8 bytes long double: 8 bytes

Your results may vary if you are using a different type of machine, or a different compiler.

I can understand that it depends on the machine.. But how does it depend on the compiler??

By: prafull.badyal

prafull.badyal — Mon, 20 Dec 2010 17:25:37 +0000

some token error is given at cout statement …relating end1; in below progg.

1
int x;
2
cout << "x is " << sizeof(x) << " bytes"<