long nMyNumber = 2147483648U;

This tells the compiler to treat the literal as an unsigned number instead of a signed one.

Double works but unsigned long does not, i get this error for unsigned long
warning: decimal integer constant is so large that it is unsigned

Whenever you’re working with floating point values (floats and doubles and long doubles), make sure you add a .0 suffix if your value is a whole number:

double dValue = 2147483648.0;

First of all thank you very much for such a great tutorial.

I have a small question, I am unable to an value more than 2,147,483,647 if though I am declaring the variable as double, long double, unsigned int. I dont understand why, I have just started learning C++ and I find your tutorial very informative.

Thanks
Lal

#include

int main()
{
long double nshort;
nshort=2147483648;
cout << “short:” << sizeof(nshort) << ” bytes” << endl;
cout <<”\n” << nshort;

}