Comments on: 2.4 — Integers http://www.learncpp.com/cpp-tutorial/24-integers/ Thu, 09 Sep 2010 12:59:21 +0000 http://wordpress.org/?v=2.9.2 hourly 1 By: Kevin http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-90822 Kevin Tue, 24 Aug 2010 21:56:08 +0000 http://www.learncpp.com/?p=44#comment-90822 Hi Alex Did you realise you were missing the number 12 and 14 from your binary example? You have: 0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1101, 1111 Should be: 0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111 Don't know if that was intentional but it certainly hurt by brain (binary newbie) figuring it out! Cheers for the awesome tutorial, I'm so grateful for your time :) Kevin Hi Alex

Did you realise you were missing the number 12 and 14 from your binary example?

You have:
0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1101, 1111
Should be:
0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111

Don’t know if that was intentional but it certainly hurt by brain (binary newbie) figuring it out!

Cheers for the awesome tutorial, I’m so grateful for your time :)

Kevin

]]> By: Aditya Dhara http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-89207 Aditya Dhara Wed, 28 Jul 2010 09:09:11 +0000 http://www.learncpp.com/?p=44#comment-89207 when you say, an int variable has a size of 2 bytes or 4 bytes, what do u mean? does it dynamically change size from 2 to 4 bytes as the number get larger? when you say, an int variable has a size of 2 bytes or 4 bytes, what do u mean? does it dynamically change size from 2 to 4 bytes as the number get larger?

]]> By: zsb http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-87043 zsb Wed, 23 Jun 2010 16:44:48 +0000 http://www.learncpp.com/?p=44#comment-87043 <pre>i have a calculator for this it is 0-1-10-11-100-101-110-111-1000-1001-1010-1011-1100-1101-1110-1111 0-15</pre> i have a calculator for this it is 0-1-10-11-100-101-110-111-1000-1001-1010-1011-1100-1101-1110-1111 0-15 ]]> By: joe http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-87011 joe Wed, 23 Jun 2010 04:36:23 +0000 http://www.learncpp.com/?p=44#comment-87011 What is the difference between the "long" and "int" variable types? (They both have the same size). What is the difference between the “long” and “int” variable types? (They both have the same size).

]]> By: joha http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-86989 joha Tue, 22 Jun 2010 18:36:07 +0000 http://www.learncpp.com/?p=44#comment-86989 I thing it is 0-1-10-11-100-101-110-111-1000-1001-1010-1011-1100-1101-1110 to make a 15 and to make a 16, just add a 1111...... Let me know if I am mistaken.....great tutorials... I thing it is 0-1-10-11-100-101-110-111-1000-1001-1010-1011-1100-1101-1110 to make a 15 and to make a 16, just add a 1111……

Let me know if I am mistaken…..great tutorials…

]]> By: mfz http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-84914 mfz Tue, 18 May 2010 21:00:37 +0000 http://www.learncpp.com/?p=44#comment-84914 For "1 byte signed" the range is -128 to 127, how is -128 represented in 1 byte, does'nt it cause an overflow? 127 => 01111111 -128 => 111111111 (the right most 1 represents - negative) Also why cant we represent 128 in 1 byte (why is the range only till 127?) 128 => 10000000 Thx For “1 byte signed” the range is -128 to 127, how is -128 represented in 1 byte, does’nt it cause an overflow?
127 => 01111111
-128 => 111111111 (the right most 1 represents – negative)

Also why cant we represent 128 in 1 byte (why is the range only till 127?)
128 => 10000000

Thx

]]> By: Subhasis Rout http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-82256 Subhasis Rout Sat, 03 Apr 2010 19:22:01 +0000 http://www.learncpp.com/?p=44#comment-82256 Can someone tell me why this does not work. <pre> unsigned char ch1=5; cout<<"The value of ch1 is : "<<ch1<<endl; </pre> As per the above lesson char is type of INT. so this should work. Can someone tell me why this does not work.

unsigned char ch1=5;
cout<<"The value of ch1 is : "<<ch1<<endl;

As per the above lesson char is type of INT. so this should work.

]]> By: Yzak http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-75642 Yzak Mon, 04 Jan 2010 03:50:37 +0000 http://www.learncpp.com/?p=44#comment-75642 oops... 12 - 1100 13 - 1101 14 - 1110 15 - 1111 oops…
12 – 1100
13 – 1101
14 – 1110
15 – 1111

]]> By: Yzak http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-75452 Yzak Sun, 03 Jan 2010 23:33:37 +0000 http://www.learncpp.com/?p=44#comment-75452 Adam, In the overflow section, I noticed you only have 14 numbers. Shouldn't there be 16 since you are starting from 0. Wouldn't it be: 0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1101, 1111 0 - 0 1 - 1 2 - 10 3 - 11 4 - 100 5 - 101 6 - 110 7 - 111 8 -1000 9 -1001 10-1010 11-1011 12-1101 13-1110 14-1111 15-10000 ? Adam,
In the overflow section, I noticed you only have 14 numbers. Shouldn’t there be 16 since you are starting from 0. Wouldn’t it be:
0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1101, 1111
0 – 0
1 – 1
2 – 10
3 – 11
4 – 100
5 – 101
6 – 110
7 – 111
8 -1000
9 -1001
10-1010
11-1011
12-1101
13-1110
14-1111
15-10000
?

]]> By: lampamp http://www.learncpp.com/cpp-tutorial/24-integers/comment-page-1/#comment-74854 lampamp Fri, 25 Dec 2009 17:49:58 +0000 http://www.learncpp.com/?p=44#comment-74854 65535 is 0011011000110101001101010011001100110101 65536 is 0011011000110101001101010011001100110110 how is short able to maintain the first but not the second? can u please explain? 65535 is 0011011000110101001101010011001100110101
65536 is 0011011000110101001101010011001100110110

how is short able to maintain the first but not the second?
can u please explain?

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