#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();

float fValue1 = 1.345f;
float fValue2 = 1.123f;
float fTotal = fValue1 + fValue2; // should be 2.468

if (fTotal == 2.468)
{
cout << "n fTotal is 2.468";
}
else
{
cout << "n fTotal is not 2.468";
}

printf("n The real value of fTotal is %0.7f", fTotal);
getch();
}

/* End of Pgram */

#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
double fValue;

float fValue1 = 1.345f;
float fValue2 = 1.123f;
float fTotal = fValue1 + fValue2; // should be 2.468

if (fTotal == 2.468)
{
cout << "n fTotal is 2.468";
}
else
{
cout << "n fTotal is not 2.468";
}

printf("n The real value of fTotal is %0.7f", fTotal);
getch();
}

/* End of Pgram */

See the lesson on ostream for more info about output manipulators and stuff.

The compiler brings up a problem with setprecision()..

#include "stdafx.h"
#include 

int main()
{
	using namespace std;

	cout < < setprecision(16);
	float fValue;
	fValue = 1.3333333333333333f;
	cout << fValue << endl;

	cin.ignore(255, '/n');
	cin.get();
	return 0;
}

Thanks ]]> http://www.learncpp.com/cpp-tutorial/25-floating-point-numbers/#comment-7592 Alex Sun, 10 Feb 2008 01:11:55 +0000 http://www.learncpp.com/?p=46#comment-7592 By default, if you type a floating point value into C++ it's typed as a double. Consequently, if you do something like this: <pre> float fValue = 4.53; // 4.53 is a double </pre> You're assigning a double to a float, which loses precision, and the compiler will probably complain. Putting an "f" after the value means that you intend that value to be a float, not a double. Then when you do this: <pre> float fValue = 4.53f; // 4.53 is a float </pre> You're assigning a float value to a float variable, which makes more sense. By default, if you type a floating point value into C++ it’s typed as a double. Consequently, if you do something like this:

float fValue = 4.53; // 4.53 is a double

You’re assigning a double to a float, which loses precision, and the compiler will probably complain.

Putting an “f” after the value means that you intend that value to be a float, not a double. Then when you do this:

float fValue = 4.53f; // 4.53 is a float

You’re assigning a float value to a float variable, which makes more sense.

I’ve been to a few sites already trying to get a grasp on these (floats/doubles) and this summation really did the trick.

Thanks!