#include “iostream”;

int main()
{
using namespace std;
char chChar;
cout <> chChar;
cout << chChar << " has ASCII code " << (int)chChar << endl;
}

char = cchar;
cin>> cchar;

if i input 10 at cchar it stores 10 as a string or as an integer?

i made the code below to make a test in order to get the
answer on the question that is above

char cchar;
cin>>cchar;
char cchar2 = 5;
cout<<cchar+cchar2<<endl;
cout<<cchar+(int)cchar2;

i input 5 and it gives me a sum of 58
on both couts, this make me understand that it takes
the input of cchar as string because as you said in the tutorial:
char chValue = '5'; // assigns 53 (ASCII code for '5')
but i cant understand why at the second cout it takes (int)cchar2 as 53 shouldnt it have the value of 5 because of the (int).
Please an answer would be appreciated.

#include “iostream”; ?

Shouldn’t it be

#include ?

Just saying.

char chValue = ’5′; // assigns 53 (ASCII code for ’5′)
char chValue2 = 5; // assigns 5

Does the bottom statement assign 5 or does it assign the character associated with the ASCII code for 5 (i.e. a club symbol)?

Thanks

If you compare each element of the array one for one (zero to zero, one to one and two to two) each element will give ’1′ for the match. In my tests, I made each array larger:
={‘s’, ‘i’, ‘n’, ‘s’}; and if you compare sss[0] to ddd[0] or sss[0] to ddd[3] they match.

To compare strings you will have to use a string-compare function. (I haven’t gotten that far yet. Just recalling unix shell and C code from my past.