void main()
{
int number;
do
{
cout <> number;
}
while(number 9);

int array[] = {1,3,2,5,8,11,4,9,21,24};

for (int index = 0; index <= 9; index++)
{
cout << array[index] << " ";
}
cout << endl << number << " has index " << array[number] << endl;

system("pause");
}

#include
using namespace std;

void main()
{
int number;
do
{
cout <> number;
}
while(number 9);

int array[] = {1,3,2,5,8,11,4,9,21,24};

for (int index = 0; index <= 9; index++)
{
cout << array[index] << " ";
}
cout << endl << number << " has index " << array[number] << endl;

system("pause");
}

int n=0 ,num;
int list[4];
int j;
cout<<"Enter 5 numbers"<> list[n])
{
n++;
if (n== 4);
//break;
}*/
for(int i=0 ; i>list[i];
}
cout<<"Enter a number "<>num;
for(j=0;j<5;j++)
{
if(list[j]==num)
{
cout<<"The number of term is: "<<j<<endl;
}
}

return 0;
}
// i know how to run it using while loop but a debug error occurs while using a for loop.
please answer

#include “stdafx.h”
#include

int main()
{
using namespace std;

int anX[9];

for(anX[0]=1; anX[0]<5; anX[0]++)
{
for(anX[1]=1; anX[1]<10; anX[1]++)
{
if(anX[0]==anX[1])
continue;
for(anX[2]=1; anX[2]<10; anX[2]++)
{
if(anX[1]==anX[2])
continue;
for(anX[3]=1; anX[3]<10; anX[3]++)
{
if(anX[2]==anX[3])
continue;
for(anX[4]=1; anX[4] 9999 || aaa < 1000)
continue;
anX[5] = aaa/1000;
anX[6] = (aaa – anX[5]*1000)/100;
anX[7] = (aaa – anX[5]*1000 – anX[6]*100)/10;
anX[8] = aaa – anX[5]*1000 – anX[6]*100 – anX[7]*10;
if(anX[5]==0 || anX[6]==0 || anX[7]==0 || anX[8]==0)
continue;
bool result = true;

for(int iii=0; iii<9; iii++)
for(int jjj=0; jjj<9; jjj++)
{
if(iii!=jjj && anX[iii]==anX[jjj])
result = false;
}
if(result)
{
cout << "The Result is?" << endl;
int bbb = anX[0]*1000 + anX[1]*100 + anX[2]*10 + anX[3];
int ccc = bbb * anX[4];
cout << bbb << " * " << anX[4] << " = " << ccc << endl;
}
}
}
}
}
}
}
cout << "The End?" << endl;
}

I’m new to learning c++, and I’m really enjoying following this tutorial.

My question is this:
When i run the program it correctly keeps asking for a number between 1 and 9 as long as i input a number when prompted. However if I input a letter (Tried it to see what would happen incase of a misstype) it seems to go into an endless loop. Is it supposed to do that (with the code written) or is there another way to avoid this problem I should implement?

#include "stdafx.h"
#include <iostream>
using namespace std;

int main()
{
	int x;
	do
	{
		cout << "Please input a number between 1 and 9: ";
		cin >> x;
	}	while (x < 1 || x > 9);

	int anArray[9] = {4, 6, 7, 3, 8, 2, 1, 9, 5};
	for (int iii = 0; iii < 9; iii++)
		cout << anArray[iii] << " ";

	cout << endl;

	for (int jjj = 0; jjj < 9; jjj++)
	{
		if (anArray[jjj] == x)
		{
			cout << "The number you entered (" << x << ") has index number: " << jjj << endl;
			break;
		}
	}

	return 0;
}

#include "stdafx.h"
#include <iostream>

int main()
{
	using namespace std;
	int nInputNumber;
	do
	{
		cout << "Please enter a number between 1 and 9: ";
		cin >> nInputNumber;
	}while((nInputNumber < 0) || (nInputNumber >= 9));

	const int nArrayElements = 9;
	int anArray[nArrayElements] = { 4, 6, 7, 3, 8, 2, 1, 9, 5 };
	cout <<"The array contains the following elements: ";
	int nInputElement = -1;  // This will hold the place of the input number.
	for(int iii = 0; iii < 9; iii++)
	{
		cout << anArray[iii] << " ";
		if(anArray[iii] == nInputNumber)
			nInputElement = iii+1;
	}
	cout << endl;
	cout << "Your number was element number " << nInputElement << "." << endl;
	return 0;
}