#include

in the code that people copy to their clipboard so that errors don’t occur?
E.g.
g++ j35.cpp -g -o xxx
j35.cpp: In function ‘int main(int, char**)’:
j35.cpp:8: error: ‘cout’ was not declared in this scope
j35.cpp:8: error: ‘endl’ was not declared in this scope
j35.cpp:9: error: ‘exit’ was not declared in this scope

That is:

#include <iostream>
int main(int argc, char *argv[])
{
    using namespace std;
    // If the user didn't provide a filename command line argument,
    // print an error and exit.
    if (argc <= 1)
    {
        cout << "Usage: " << argv[0] << " <Filename>" << endl;
        exit(1);
    }

    char *pFilename = argv[1];

    // open file and process it
}

// This should work
wcout << argv[0] << endl;

    if (argc <= 1)
    {
        cout << "Usage: " << argv[0] << " <Filename>" << endl;
        exit(1);
    }

When there is a command line argument, argc = 1 then (argc <= 1) is the same as 1 <=1 what translates to true so the program exits.
It should be like this no?

    if (argc < 1)