Isn’t it more likely the c++ runtime that deletes arrays? So the compiler cannot tell how big an allocated array will be (becuase it can be allocated by a variable amount). So if you want an array you can tell the siz of, you should use an stl vector.

Nice Tutorial btw.. i’m using this to learn c++ :)

great tutorial! It’s so amazing simple to learn C with your help, I’ve never thought before.

I’ve found a little error he links aren’t correct:

« 7.14 — Ellipses (and why to avoid them)
  13.1 — Input and output (I/O) streams »

new int[]

but rather something like

int* apArray = int* npPtr

it is most likely that the compiler does not take it as an Array.
Try this:

delete apArray

Then access to any element will result in garbage

std::cout <<  apArray[0];

Once again, this is my guess. Hopefully Alex or someone else can verify this.

BTW, great tutorial Alex! Thanks a ton.

#include<iostream>

int* CreateArray(int nSize)
{
	int* const npPtr = new int[nSize];

	//initialize the array
	for (int iii=0;iii<nSize;iii++)
		npPtr[iii]=iii;
	return npPtr;
}

int main()
{
	int nSize=5;
	int *apArray=CreateArray(nSize);
	delete[] apArray;
	system("pause");
	return 0;
}

Thanks :)

plese see the code below and kindly give your comments..

result of below code is 

Hello World!
res = 7
res1 = 12

int add (int x, int y)
{
int result = x+y;
return result;
}

// return by reference
int& multiply(int x, int y)
{
 int result = x*y;
 return result;
}

int main(int argc, char* argv[])
{
	printf("Hello World!\n");
	int res = add(3,4);
	std::cout<< "res = " << res << std::endl; 

	int res1 = multiply(3,4);
	std::cout << "res1 = " << res1 << std::endl;
	return 0;
}