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15.1 — Intro to smart pointers and move semantics

Consider a function in which we dynamically allocate a value:

Although the above code seems fairly straightforward, it’s fairly easy to forget to deallocate ptr. Even if you do remember to delete ptr at the end of the function, there are a myriad of ways that ptr may not be deleted if the function exits early. This can happen via an early return:

or via a thrown exception:

In the above two programs, the early return or throw statement execute, causing the function to terminate without variable ptr being deleted. Consequently, the memory allocated for variable ptr is now leaked (and will be leaked again every time this function is called and returns early).

At heart, these kinds of issues occur because pointer variables have no inherent mechanism to clean up after themselves.

Smart pointer classes to the rescue?

One of the best things about classes is that they contain destructors that automatically get executed when an object of the class goes out of scope. So if you allocate (or acquire) memory in your constructor, you can deallocate it in your destructor, and be guaranteed that the memory will be deallocated when the class object is destroyed (regardless of whether it goes out of scope, gets explicitly deleted, etc…). This is at the heart of the RAII programming paradigm that we talked about in lesson 8.7 -- Destructors.

So can we use a class to help us manage and clean up our pointers? We can!

Consider a class whose sole job was to hold and “own” a pointer passed to it, and then deallocate that pointer when the class object went out of scope. As long as objects of that class were only created as local variables, we could guarantee that the class would properly go out of scope (regardless of when or how our functions terminate) and the owned pointer would get destroyed.

Here’s a first draft of the idea:

This program prints:

Resource acquired
Resource destroyed

Consider how this program and class work. First, we dynamically create a Resource, and pass it as a parameter to our templated Auto_ptr1 class. From that point forward, our Auto_ptr1 variable res owns that Resource object (Auto_ptr1 has a composition relationship with m_ptr). Because res is declared as a local variable and has block scope, it will go out of scope when the block ends, and be destroyed (no worries about forgetting to deallocate it). And because it is a class, when it is destroyed, the Auto_ptr1 destructor will be called. That destructor will ensure that the Resource pointer it is holding gets deleted!

As long as Auto_ptr1 is defined as a local variable (with automatic duration, hence the “Auto” part of the class name), the Resource will be guaranteed to be destroyed at the end of the block it is declared in, regardless of how the function terminates (even if it terminates early).

Such a class is called a smart pointer. A Smart pointer is a composition class that is designed to manage dynamically allocated memory and ensure that memory gets deleted when the smart pointer object goes out of scope. (Relatedly, built-in pointers are sometimes called “dumb pointers” because they can’t clean up after themselves).

Now let’s go back to our someFunction() example above, and show how a smart pointer class can solve our challenge:

If the user enters a non-zero integer, the above program will print:

Resource acquired
Hi!
Resource destroyed

If the user enters zero, the above program will terminate early, printing:

Resource acquired
Resource destroyed

Note that even in the case where the user enters zero and the function terminates early, the Resource is still properly deallocated.

Because the ptr variable is a local variable, ptr will be destroyed when the function terminates (regardless of how it terminates). And because the Auto_ptr1 destructor will clean up the Resource, we are assured that the Resource will be properly cleaned up.

A critical flaw

The Auto_ptr1 class has a critical flaw lurking behind some auto-generated code. Before reading further, see if you can identify what it is. We’ll wait…

(Hint: consider what parts of a class get auto-generated if you don’t supply them)

(Jeopardy music)

Okay, time’s up.

Rather than tell you, we’ll show you. Consider the following program:

This program prints:

Resource acquired
Resource destroyed
Resource destroyed

Very likely (but not necessarily) your program will crash at this point. See the problem now? Because we haven’t supplied a copy constructor or an assignment operator, C++ provides one for us. And the functions it provides do shallow copies. So when we initialize res2 with res1, both Auto_ptr1 variables are pointed at the same Resource. When res2 goes out of the scope, it deletes the resource, leaving res1 with a dangling pointer. When res1 goes to delete its (already deleted) Resource, crash!

You’d run into a similar problem with a function like this:

In this program, res1 will be copied by value into passByValue’s parameter res, leading to duplication of the Resource pointer. Crash!

So clearly this isn’t good. How can we address this?

Well, one thing we could do would be to explicitly define and delete the copy constructor and assignment operator, thereby preventing any copies from being made in the first place. That would prevent the pass by value case (which is good, we probably shouldn’t be passing these by value anyway).

But then how would we return an Auto_ptr1 from a function back to the caller?

We can’t return our Auto_ptr1 by reference, because the local Auto_ptr1 will be destroyed at the end of the function, and the caller will be left with a dangling reference. Return by address has the same problem. We could return pointer r by address, but then we might forget to delete r later, which is the whole point of using smart pointers in the first place. So that’s out. Returning the Auto_ptr1 by value is the only option that makes sense -- but then we end up with shallow copies, duplicated pointers, and crashes.

Another option would be to override the copy constructor and assignment operator to make deep copies. In this way, we’d at least guarantee to avoid duplicate pointers to the same object. But copying can be expensive (and may not be desirable or even possible), and we don’t want to make needless copies of objects just to return an Auto_ptr1 from a function. Plus assigning or initializing a dumb pointer doesn’t copy the object being pointed to, so why would we expect smart pointers to behave differently?

What do we do?

Move semantics

What if, instead of having our copy constructor and assignment operator copy the pointer (“copy semantics”), we instead transfer/move ownership of the pointer from the source to the destination object? This is the core idea behind move semantics. Move semantics means the class will transfer ownership of the object rather than making a copy.

Let’s update our Auto_ptr1 class to show how this can be done:

This program prints:

Resource acquired
res1 is not null
res2 is null
Ownership transferred
res1 is null
res2 is not null
Resource destroyed

Note that our overloaded operator= gave ownership of m_ptr from res1 to res2! Consequently, we don’t end up with duplicate copies of the pointer, and everything gets tidily cleaned up.

std::auto_ptr, and why to avoid it

Now would be an appropriate time to talk about std::auto_ptr. std::auto_ptr, introduced in C++98, was C++’s first attempt at a standardized smart pointer. std::auto_ptr opted to implement move semantics just like the Auto_ptr2 class does.

However, std::auto_ptr (and our Auto_ptr2 class) has a number of problems that makes using it dangerous.

First, because std::auto_ptr implements move semantics through the copy constructor and assignment operator, passing a std::auto_ptr by value to a function will cause your resource to get moved to the function parameter (and be destroyed at the end of the function when the function parameters go out of scope). Then when you go to access your auto_ptr argument from the caller (not realizing it was transferred and deleted), you’re suddenly dereferencing a null pointer. Crash!

Second, std::auto_ptr always deletes its contents using non-array delete. This means auto_ptr won’t work correctly with dynamically allocated arrays, because it uses the wrong kind of deallocation. Worse, it won’t prevent you from passing it a dynamic array, which it will then mismanage, leading to memory leaks.

Finally, auto_ptr doesn’t play nice with a lot of the other classes in the standard library, including most of the containers and algorithms. This occurs because those standard library classes assume that when they copy an item, it actually makes a copy, not does a move.

Because of the above mentioned shortcomings, std::auto_ptr has been deprecated in C++11, and it should not be used. In fact, std::auto_ptr is slated for complete removal from the standard library as part of C++17!

Rule: std::auto_ptr is deprecated and should not be used. (Use std::unique_ptr or std::shared_ptr instead)..

Moving forward

The core problem with the design of std::auto_ptr is that prior to C++11, the C++ language simply had no mechanism to differentiate “copy semantics” from “move semantics”. Overriding the copy semantics to implement move semantics leads to weird edge cases and inadvertent bugs. For example, you can write res1 = res2 and have no idea whether res2 will be changed or not!

Because of this, in C++11, the concept of “move” was formally defined, and “move semantics” were added to the language to properly differentiate copying from moving. Now that we’ve set the stage for why move semantics can be useful, we’ll explore the topic of move semantics throughout the rest of this chapter. We’ll also fix our Auto_ptr2 class using move semantics.

In C++11, std::auto_ptr has been replaced by a bunch of other types of “move-aware” smart pointers: std::scoped_ptr, std::unique_ptr, std::weak_ptr, and std::shared_ptr. We’ll also explore the two most popular of these: unique_ptr (which is a direct replacement for auto_ptr) and shared_ptr.

15.2 -- R-value references
Index
14.x -- Chapter 14 comprehensive quiz

78 comments to 15.1 — Intro to smart pointers and move semantics

  • Yogesh

    I am trying to delete the ptr before assigning to new value in copy constructor(like assignment operator) , but doing that ,i am getting error.
    Could you please help me to root cause the error .

  • Danty Wong

    Hi,

    When res2 is declared, only a chunk of memory large enough for a Resource class object is set aside, so no constructor is called for creating res2.
    In the middle of the programme, the content of res1's m_ptr field is 'moved' to res2's m_ptr field. At what point does res2 gets its m_ptr field declared?

    At the end of the programme, only one line of "Resource destroyed" is printed. Is this from the destructor of res1 or res2? And if only one of the destructor is called, what about the other object in the block? Does it get destroyed as well?

    Thanks

    • Alex

      > When res2 is declared, only a chunk of memory large enough for a Resource class object is set aside, so no constructor is called for creating res2.

      No, when res2 is declared, an Auto_ptr2 is allocated, which contains a null pointer (m_ptr). No memory is set aside for a Resource object.

      When the move happens, the res1's m_ptr is transfered to res2's m_ptr. At this point, res1's m_ptr is set to null, as it no longer owns the object.

      At the end, the destructor is called from res2, as res2 is the owner of the resource.

      There is no other object in the block -- there's only one Resource (destroyed by res2) and two Auto_ptr2 that are automatically deallocated when the function ends.

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