15.4a — std::move_if_noexcept

(h/t to reader Koe for providing the first draft of this lesson!)

In lesson 14.9 -- Exception specifications and noexcept, we covered the noexcept exception specifier and operator, which this lesson builds on.

We also covered the strong exception guarantee, which guarantees that if a function is interrupted by an exception, no memory will be leaked and the program state will not be changed. In particular, all constructors should uphold the strong exception guarantee, so that the rest of the program won’t be left in an altered state if construction of an object fails.

The move constructors exception problem

Consider the case where we are copying some object, and the copy fails for some reason (e.g. the machine is out of memory). In such a case, the object being copied is not harmed in any way, because the source object doesn’t need to be modified to create a copy. We can discard the failed copy, and move on. The strong exception guarantee is upheld.

Now consider the case where we are instead moving an object. A move operation transfers ownership of a given resource from the source to the destination object. If the move operation is interrupted by an exception after the transfer of ownership occurs, then our source object will be left in a modified state. This isn’t a problem if the source object is a temporary object and going to be discarded after the move anyway -- but for non-temporary objects, we’ve now damaged the source object. To comply with the strong exception guarantee, we’d need to move the resource back to the source object, but if the move failed the first time, there’s no guarantee the move back will succeed either.

How can we give move constructors the strong exception guarantee? It is simple enough to avoid throwing exceptions in the body of a move constructor, but a move constructor may invoke other constructors that are potentially throwing. Take for example the move constructor for std::pair, which must try to move each subobject in the source pair into the new pair object.

Now lets use two classes, MoveClass and CopyClass, which we will pair together to demonstrate the strong exception guarantee problem with move constructors:

The above program prints:

destroying MoveClass(empty)
my_pair.first: MoveClass(13)
destroying MoveClass(13)
Error found: abort!
my_pair.first: MoveClass(empty)
destroying MoveClass(empty)

Let’s explore what happened. The first printed line shows the temporary MoveClass object used to initialize my_pair gets destroyed as soon as the my_pair instantiation statement has been executed. It is empty since the MoveClass subobject in my_pair was move constructed from it, demonstrated by the next line which shows my_pair.first contains the MoveClass object with value 13.

It gets interesting in the third line. We created moved_pair by copy constructing its CopyClass subobject (it doesn’t have a move constructor), but that copy construction threw an exception since we changed the Boolean flag. Construction of moved_pair was aborted by the exception, and its already-constructed members were destroyed. In this case, the MoveClass member was destroyed, printing destroying MoveClass(13) variable. Next we see the Error found: abort! message printed by main().

When we try to print my_pair.first again, it shows the MoveClass member is empty. Since moved_pair was initialized with std::move, the MoveClass member (which has a move constructor) got move constructed and my_pair.first was nulled.

Finally, my_pair was destroyed at the end of main().

To summarize the above results: the move constructor of std::pair used the throwing copy constructor of CopyClass. This copy constructor throw an exception, causing the creation of moved_pair to abort, and my_pair.first to be permanently damaged. The strong exception guarantee was not preserved.

std::move_if_noexcept to the rescue

Note that the above problem could have been avoided if std::pair had tried to do a copy instead of a move. In that case, moved_pair would have failed to construct, but my_pair would not have been altered.

But copying instead of moving has a performance cost that we don’t want to pay for all objects -- ideally we want to do a move if we can do so safely, and a copy otherwise.

Fortunately, C++ has a two mechanisms that, when used in combination, let us do exactly that. First, because noexcept functions are no-throw/no-fail, they implicitly meet the criteria for the strong exception guarantee. Thus, a noexcept move constructor is guaranteed to succeed.

Second, we can use the standard library function std::move_if_noexcept() to determine whether a move or a copy should be performed. std::move_if_noexcept is a counterpart to std::move, and is used in the same way.

If the compiler can tell that an object passed as an argument to std::move_if_noexcept won’t throw an exception when it is move constructed (or if the object is move-only and has no copy constructor), then std::move_if_noexcept will perform identically to std::move() (and return the object converted to an r-value). Otherwise, std::move_if_noexcept will return a normal l-value reference to the object.

Key insight

std::move_if_noexcept will return a movable r-value if the object has a noexcept move constructor, otherwise it will return a copyable l-value. We can use the noexcept specifier in conjunction with std::move_if_noexcept to use move semantics only when a strong exception guarantee exists (and use copy semantics otherwise).

Let’s update the code in the previous example as follows:

Running the program again prints:

destroying MoveClass(empty)
my_pair.first: MoveClass(13)
destroying MoveClass(13)
Error found: abort!
my_pair.first: MoveClass(13)
destroying MoveClass(13)

As you can see, after the exception was thrown, the subobject my_pair.first still points to the value 13.

CopyClass doesn’t have a noexcept move constructor, so std::move_if_noexcept returns my_pair as an l-value reference. This causes moved_pair to be created via the copy constructor (rather than the move constructor). The copy constructor can throw safely, because it doesn’t modify the source object.

The standard library uses std::move_if_noexcept often to optimize for functions that are noexcept. For example, std::vector::resize will use move semantics if the element type has a noexcept move constructor, and copy semantics otherwise. This means std::vector will generally operate faster with objects that have a noexcept move constructor (reminder: move constructors are noexcept by default, unless they call a function that is noexcept(false)).


If a type has both potentially throwing move semantics and deleted copy semantics (the copy constructor and copy assignment operator are unavailable), then std::move_if_noexcept will waive the strong guarantee and invoke move semantics. This conditional waiving of the strong guarantee is ubiquitous in the standard library container classes, since they use std::move_if_noexcept often.

15.5 -- std::unique_ptr
15.4 -- std::move

5 comments to 15.4a — std::move_if_noexcept

  • Marat

    I noticed that you specify move constructors as noexcept in previous lessons, but it's missing here.

  • Dong

    - I run this example in Code::Block, The result shows an error "missing template arguments before my_pair"

    I do not understand what happens? Can you explain this problem? Thanks for you advices.

    • nascardriver

      You need at least C++17 to run this example. Before that, you had to explicitly specify the template arguments

  • koe

    <3 thanks :)

    - "Example move constructor declaration" -> definition
    - the copy constructor of MoveClass doesn't need a self-assignment check
    - "both a potentially throwing move semantics" -> /a\

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