4.11 — Chars

To this point, the fundamental data types we’ve looked at have been used to hold numbers (integers and floating point) or true/false values (booleans). But what if we want to store letters? The char data type was designed for such a purpose.

The char data type is an integral type, meaning the underlying value is stored as an integer, and it’s guaranteed to be 1-byte in size. However, similar to how a boolean value is interpreted as true or false, a char value is interpreted as an ASCII character.

ASCII stands for American Standard Code for Information Interchange, and it defines a particular way to represent English characters (plus a few other symbols) as numbers between 0 and 127 (called an ASCII code or code point). For example, ASCII code 97 is interpreted as the character ‘a’.

Character literals are always placed between single quotes.

Here’s a full table of ASCII characters:

Code Symbol Code Symbol Code Symbol Code Symbol
0 NUL (null) 32 (space) 64 @ 96 `
1 SOH (start of header) 33 ! 65 A 97 a
2 STX (start of text) 34 66 B 98 b
3 ETX (end of text) 35 # 67 C 99 c
4 EOT (end of transmission) 36 $ 68 D 100 d
5 ENQ (enquiry) 37 % 69 E 101 e
6 ACK (acknowledge) 38 & 70 F 102 f
7 BEL (bell) 39 71 G 103 g
8 BS (backspace) 40 ( 72 H 104 h
9 HT (horizontal tab) 41 ) 73 I 105 i
10 LF (line feed/new line) 42 * 74 J 106 j
11 VT (vertical tab) 43 + 75 K 107 k
12 FF (form feed / new page) 44 , 76 L 108 l
13 CR (carriage return) 45 - 77 M 109 m
14 SO (shift out) 46 . 78 N 110 n
15 SI (shift in) 47 / 79 O 111 o
16 DLE (data link escape) 48 0 80 P 112 p
17 DC1 (data control 1) 49 1 81 Q 113 q
18 DC2 (data control 2) 50 2 82 R 114 r
19 DC3 (data control 3) 51 3 83 S 115 s
20 DC4 (data control 4) 52 4 84 T 116 t
21 NAK (negative acknowledge) 53 5 85 U 117 u
22 SYN (synchronous idle) 54 6 86 V 118 v
23 ETB (end of transmission block) 55 7 87 W 119 w
24 CAN (cancel) 56 8 88 X 120 x
25 EM (end of medium) 57 9 89 Y 121 y
26 SUB (substitute) 58 : 90 Z 122 z
27 ESC (escape) 59 ; 91 [ 123 {
28 FS (file separator) 60 < 92 \ 124 |
29 GS (group separator) 61 = 93 ] 125 }
30 RS (record separator) 62 > 94 ^ 126 ~
31 US (unit separator) 63 ? 95 _ 127 DEL (delete)

Codes 0-31 are called the unprintable chars, and they’re mostly used to do formatting and control printers. Most of these are obsolete now.

Codes 32-127 are called the printable characters, and they represent the letters, number characters, and punctuation that most computers use to display basic English text.

Initializing chars

You can initialize char variables using character literals:

You can initialize chars with integers as well, but this should be avoided if possible


Be careful not to mix up character numbers with integer numbers. The following two initializations are not the same:

Character numbers are intended to be used when we want to represent numbers as text, rather than as numbers to apply mathematical operations to.

Printing chars

When using std::cout to print a char, std::cout outputs the char variable as an ASCII character:

This produces the result:


We can also output char literals directly:

This produces the result:


A reminder

The fixed width integer int8_t is usually treated the same as a signed char in C++, so it will generally print as a char instead of an integer.

Printing chars as integers via type casting

If we want to output a char as a number instead of a character, we have to tell std::cout to print the char as if it were an integer. One (poor) way to do this is by assigning the char to an integer, and printing the integer:

However, this is clunky. A better way is to use a type cast. A type cast creates a value of one type from a value of another type. To convert between fundamental data types (for example, from a char to an int, or vice versa), we use a type cast called a static cast.

The syntax for the static cast looks a little funny:


static_cast takes the value from an expression as input, and converts it into whatever fundamental type new_type represents (e.g. int, bool, char, double).

Key insight

Whenever you see C++ syntax (excluding the preprocessor) that makes use of angled brackets, the thing between the angled brackets will most likely be a type. This is typically how C++ deals with concepts that need a parameterizable type.

Here’s using a static cast to create an integer value from our char value:

This results in:


It’s important to note that the parameter to static_cast evaluates as an expression. When we pass in a variable, that variable is evaluated to produce its value, which is then converted to the new type. The variable is not affected by casting its value to a new type. In the above case, variable ch is still a char, and still holds the same value.

Also note that static casting doesn’t do any range checking, so if you cast a large integer into a char, you’ll overflow your char.

We’ll talk more about static casts and the different types of casts in a future lesson (6.16 -- Explicit type conversion (casting) and static_cast).

Inputting chars

The following program asks the user to input a character, then prints out both the character and its ASCII code:

Here’s the output from one run:

Input a keyboard character: q
q has ASCII code 113

Note that std::cin will let you enter multiple characters. However, variable ch can only hold 1 character. Consequently, only the first input character is extracted into variable ch. The rest of the user input is left in the input buffer that std::cin uses, and can be extracted with subsequent calls to std::cin.

You can see this behavior in the following example:

Input a keyboard character: abcd
a has ASCII code 97
b has ASCII code 98

Char size, range, and default sign

Char is defined by C++ to always be 1 byte in size. By default, a char may be signed or unsigned (though it’s usually signed). If you’re using chars to hold ASCII characters, you don’t need to specify a sign (since both signed and unsigned chars can hold values between 0 and 127).

If you’re using a char to hold small integers (something you should not do unless you’re explicitly optimizing for space), you should always specify whether it is signed or unsigned. A signed char can hold a number between -128 and 127. An unsigned char can hold a number between 0 and 255.

Escape sequences

There are some characters in C++ that have special meaning. These characters are called escape sequences. An escape sequence starts with a ‘\’ (backslash) character, and then a following letter or number.

You’ve already seen the most common escape sequence: ‘\n’, which can be used to embed a newline in a string of text:

This outputs:

First line
Second line

Another commonly used escape sequence is ‘\t’, which embeds a horizontal tab:

Which outputs:

First part        Second part

Three other notable escape sequences are:
\’ prints a single quote
\” prints a double quote
\\ prints a backslash

Here’s a table of all of the escape sequences:

Name Symbol Meaning
Alert \a Makes an alert, such as a beep
Backspace \b Moves the cursor back one space
Formfeed \f Moves the cursor to next logical page
Newline \n Moves cursor to next line
Carriage return \r Moves cursor to beginning of line
Horizontal tab \t Prints a horizontal tab
Vertical tab \v Prints a vertical tab
Single quote \’ Prints a single quote
Double quote \” Prints a double quote
Backslash \\ Prints a backslash.
Question mark \? Prints a question mark.
No longer relevant. You can use question marks unescaped.
Octal number \(number) Translates into char represented by octal

Hex number \x(number) Translates into char represented by hex number

Here are some examples:


"This is quoted text"
This string contains a single backslash \
6F in hex is char 'o'

Newline (\n) vs. std::endl

We cover this topic in lesson 1.5 -- Introduction to iostream: cout, cin, and endl.

What’s the difference between putting symbols in single and double quotes?

Stand-alone chars are always put in single quotes (e.g. ‘a’, ‘+’, ‘5’). A char can only represent one symbol (e.g. the letter a, the plus symbol, the number 5). Something like this is illegal:

Text put between double quotes (e.g. “Hello, world!”) is called a string. A string is a collection of sequential characters (and thus, a string can hold multiple symbols).

For now, you’re welcome to use string literals in your code:

However, strings are not fundamental data types in C++, and are a little more complex, so we’ll reserve discussion of those until we cover compound types.


Always put stand-alone chars in single quotes (e.g. ‘t’ or ‘\n’, not “t” or “\n”). This helps the compiler optimize more effectively.

What about the other char types, wchar_t, char16_t, and char32_t?

wchar_t should be avoided in almost all cases (except when interfacing with the Windows API). Its size is implementation defined, and is not reliable. It has largely been deprecated.

As an aside...

The term “deprecated” means “still supported, but no longer recommended for use, because it has been replaced by something better or is no longer considered safe”.

Much like ASCII maps the integers 0-127 to American English characters, other character encoding standards exist to map integers (of varying sizes) to characters in other languages. The most well-known mapping outside of ASCII is the Unicode standard, which maps over 110,000 integers to characters in many different languages. Because Unicode contains so many code points, a single Unicode code point needs 32-bits to represent a character (called UTF-32). However, Unicode characters can also be encoded using multiple 16-bit or 8-bit characters (called UTF-16 and UTF-8 respectively).

char16_t and char32_t were added to C++11 to provide explicit support for 16-bit and 32-bit Unicode characters. char8_t has been added in C++20.

You won’t need to use char8_t, char16_t, or char32_t unless you’re planning on making your program Unicode compatible. Unicode and localization are generally outside the scope of these tutorials, so we won’t cover it further.

In the meantime, you should only use ASCII characters when working with characters (and strings). Using characters from other character sets may cause your characters to display incorrectly.

4.12 -- Literals
4.10 -- Introduction to if statements

259 comments to 4.11 — Chars

  • Jim


    No big deal but your missing a std:: before endl here
    std::cout << "First linenSecond line" << endl;

    These may be dumb questions but is it pretty common to have extra data left in the input buffer? Would you ever want to do that in a program? If you can use endl to make sure the output buffer is emptied, is there a way make sure the input buffer is emptied? Would you ever need to do this?

    To me char,is probably one of the most confusing basic data types in C++. Since char can be both a number or a letter. Signed or unsigned and both can be the default.

    Do you ever have to use the word unsigned with char, isn't char all you need?

    Since ASCII uses the positive signed char(int). How do you call out signed negatives -1 to-128?  

    In this lesson you initialized a char ch1(97)and char ch2('a') and you wrote they both are the same 97. Isn't int8_t(97) also the same?

    I'm still a bit confused as to when and where to us the code number(97)and the code character ('a'). Is this right? if you initialize char with the code in the previous paragraph then cout will always outputs the (a) character, unless you assign it to an integer with int i(ch1), then
    it willprint out 97.

    • Alex

      Thanks for pointing out the typo. Fixed.

      Generally input being left in the input buffer is the result of the user entering something unexpected (e.g. a number instead of a letter or vice versa). In such cases, you'll likely want to clean out the extraneous input, which you can do as follows:

      You can use unsigned char if you want, but I recommend you avoid it outside of very specific instances such as bit-fields.

      > Since ASCII uses the positive signed char(int). How do you call out signed negatives -1 to-128?

      I'm not sure what you're asking here.

      In most cases, int8_t is treated the same as a signed char. But this isn't guaranteed, so don't depend on it!

      97 and 'a' are identical (both resolve to integer 97) -- however, you can use them contextually to provide the reader a clue as to your intent. Use 97 when you intend 97 to be a number, and 'a' when you intend 'a' to be treated as a character.

      • Jim

        Thanks for the quick reply.
        Maybe I'm reading to much into char and confusing myself. Since char is an integer aren't all negative char just used as constants in the range of -1 to -128. What is the proper syntax to us? char(-128) or int(-128)?

        Can you show a couple of instance on how to use them maybe that will square me away?

        • Alex

          Yes, chars are integers and as such, you can assign integer values to them directly.

          You can also assign chars to them:

  • shawn

    when i use v in the line

    then instead of working as a vertical tab v is replaced by a symbol in output string which is a ring wid a small arrow . I am using visual studio 2015. can u plz tell me the reason

  • Abdullah Shwaiky

    Hello people I need some help in here

    I have a homework about the char, we didn't take the lesson yet

    Here's what he gave me:

    "I want you to try to code a program that does the following:
    - Define a variable of type "char".
    - Ask the user to enter a capital letter and store it in the variable (using cin).
    - Cout the variable.
    - Cout (the variable + 32) (Example: cout << c + 32 << endl).
    What do you notice? How can you explain this?"

    I have done everything correctly

    But I just can't preview the small letter.

    Please help!!

  • Amandeep

    Why do these two declarations give different results while printing?
    char ch('8');
    cout<< ch <<endl; //prints 8, as expected
    char32_t ch1('8');
    cout<< ch1 <<endl; // prints code point for 8, that is, 56......why?????

    • Alex

      I can't say for sure, but I can think of two possibilities. char32_t is supposed to be a distinct type, but:
      1) It's possible your compiler has implemented char32_t as a typedef of integer, so cout is treating it as an integer for printing.
      2) It's possible that cout has decided that char32_t should printed as an integer since the Windows console font is horrible doesn't have support for most unicode code points.

      It's worth noting that C++ really only has partial support for char16_t and char32_t. While there's now a data type to hold the values, the iostream library doesn't provide support for dealing with these types.

  • Amandeep

    I never use "return 0" at the end of my main() and my programs work fine. So why is it used in every program here? Are there some special cases where not using "return 0" will lead to errors or is it just a standard practice?

    • Alex

      In C++, the main function must return a value to the operating system. We typically return 0 to indicate that "the program ran okay".

      Some compilers (such as Visual Studio) will let you omit the return value in main (they'll return 0 for you), but best practice is not to rely on this.

  • "cout outputs the char variable as an ASCII character instead of a number", Alex please tell me how cin takes input from a user. As an ASCII code or simple keyboard character. This program is a bit tricky for me:

    Suppose someone entered 9 as input for variable ch. When cout is printing result, 9 remains 9 (before static_cast) and cout does not interpret it as  ASCII code. When cin is removed from the program and ch is given a value like this:

    It produces "b has ASCII code 98". Sorry, if I am so stupid, but why results are different in above cases. Does cin takes input in this form:

    One more thing. When I assign 98 with single quotes to a char variable (char ch(’98’)), my compiler warns me that the variable is given a multi-character constant. On running the program, cout only prints the last digit (e.g. 8 for 98). Why so?

    • Alex

      In your top example, ch is of type char, so when the user inputs '9', "cin >> ch" will treat the user input as '9' (the character) and not 9 (the integer).

      If you had defined ch as an int, "cin >> ch" would have treated the input as 9 (the integer) instead. If ch was defined as a string, "cin >> ch" would have treated the input as "9" (the string) instead.

      So, in other words, cin looks at the data type of the variable being input into, and infers what the most appropriate value should be from that.

      Remember that chars can only hold a single char. '98' is two chars, which is why you are getting a warning. Visual Studio at least seems to truncate this to the last character. I'm not sure why they made that decision instead of treating it as an error.

  • The Razer

    is string a char type ?
    for example :

    can you explane a little about this variable type ?

    • Alex

      string isn't a char type. string is a special type of object called a class, and explaining classes at this point would be complicated.

      You can think of a string as a sequential collection of chars (each character in "qwerty" is a char).

  • Robin

    Where you say
    the <new_type> gets parsed as html and is not showing
    using static_cast&lt;new_type&gt;(expression) would fix this

  • AK

    You have suggested to use std::endl when you need to ensure your output is output immediately and use ‘\n’ in other cases.

    But I see the both are line buffered. i.e., both output the full output buffer when used.

    • Alex

      When printing to a console, this is generally true. However, when writing to disk, '\n' may not cause any buffered input to be written to disk immediately, whereas std::end will.

  • Todd


    "When using cout to print a char, cout outputs the char variable as an ASCII characters (character) instead of a number"

    "The rest of the user input is left in the input buffer that cin uses, and can be access (accessed) with subsequent calls to cin."

  • Aditya

    Even if the value of 'op' the user enters is not ;+; or '-', i do not get the invalid operator output. It assumes op=- and caries out subtraction
    I understand that i could use switch case to get the desired result, I am curious as to why this fails.


  • Alex

    I want to tell you how much I appreciate this tutorial - and ask one question/clarification.

    I am just learning C++ so I can create a stand-alone application for my daughter.  I have previously coded in php, bash, java and html, but this is my first crack at a compiled program.  I (as usual) just dove in and started trying some things (usually worked best for me) but found numerous topics in C++ confusing so started looking for more help.

    I found this site and it has been wonderful!  It lets me learn by trying - something I like to do - AND it explains the why of things - something I need to really learn something.  

    Thank you.  

    I do have one question.

    In the example above where you have:

    is that supposed to be:

    If so, I understand what you are saying.

    If not, I am not sure what you are getting at.

    Thanks again for making this interesting, informative and educational.


    • Damien

      Hey Ramblin
      I am just learning also but I think the way it shows is correct.

      I don't think Alex was trying to illustrate that they will both print the same. In fact I think he was trying to show how the use of the single quotes changes the value that is initialised.

  • Twisted Code

    Why does the questionmark character have an escape sequence? Does "?" do something special in a string or character-typed object? If so, what chapter can I jump to to find out more?

  • Dan Downs

    Your introduction to ASCII took me back decades, when ASCII was new and slowly replacing Baudot code used by teletypes. I was an AF communications tech, we still had tube equipment while integrated circuits were coming out and the biggest fastest communications terminal we had was the IBM 360 to do a job done by a single chip today. Some of those characters below char(32) were vital to digital transmission, which consisted of 80 character blocks transmitted synchronously at speeds up to 1200 baud (about 1.2 kB/s) using very expensive modems. SOH, ETX, EOM, ACK NAK and SYN for example were critical at the time. Of course they are obsolete but they certainly played an important roll in their day.  Thanks for the memories.  The tutorial is very good, thank you.

  • I think there is typo in the sentence below(should be 'char' instead of 'chat'):

    "The following two initializations both initialize the chat with integer value 97:"

    Also, the syntax for static_cast could have been(just saying):

  • Jeremy

    You can also print a char as a number using "integral promotion". Basically a unary + or - operator to the left of the variable:

    #include <iostream>

    int main()
        char chLetter = 'a';

        std::cout << chLetter << std::endl;

        // the unary + operator gives the integer value of a char:
        std::cout << +chLetter << std::endl;

        // the unary - operation gives the negative integer value of a char:
        std::cout << -chLetter << std::endl;

        // integral promotions are "value preserving" and do not change the value of the variable:
        std::cout << chLetter << std::endl;

        return 0;

  • Hey

    Thanks for this tut, it's very useful for me.

    First; after title "Escape sequences" in line 2 you wrote \\. should not that be \?

    Second; can you bring an example for \(number)?

    • Alex

      Fixed and done. I used the hex escape code instead of the octal escape code because hex is more commonly used in programming than octal. I can't remember the last time I used octal.

  • werthkew

    Can anyone tell me why the following program prints "-128" to the screen for chValue2?


    char chValue1 = 'a';
    char chValue2 = 128;

    int main()
    using namespace std;
    cout << chValue1 << endl;
    cout << (int)chValue2 << endl;
    return 0;

    • Xanth

      A char variable is only one byte, which means it can only hold 256 values. If it's signed (most compilers automatically sign variables) that means it can only hold integers from -128 to 127. If you unsign the variable using the unsigned command it'll be able to hold integers from 0 to 255. I ran the program to test it and if you unsign your char variable it works like a charm as long as you don't assign it anything higher than 255.

    • Alex

      Your chars are apparently signed by default (which is common).

      128 is outside the range for signed chars, so you're overflowing your char and it's wrapping around to the next number, which is -128.

      When you cast -128 to an int (also signed by default), cout prints it as -128.

  • dice3000

    cout << "\a";

    best thing ever :D

  • lan

    Please i need some help here.
    For example on these lines of code

    char = cchar;
    cin>> cchar;

    if i input 10 at cchar it stores 10 as a string or as an integer?

    i made the code below to make a test in order to get the
    answer on the question that is above

    char cchar;
    char cchar2 = 5;

    i input 5 and it gives me a sum of 58
    on both couts, this make me understand that it takes
    the input of cchar as string because as you said in the tutorial:
    char chValue = '5'; // assigns 53 (ASCII code for '5')
    but i cant understand why at the second cout it takes (int)cchar2 as 53 shouldnt it have the value of 5 because of the (int).
    Please an answer would be appreciated.

    • You answered your own question - it stores 53, because as you said, it stores the ASCII code. when you add the (int), nothing changes, because cchar2 already has an int in it (53), hence it still thinks of it as 53.

  • Jupi

    Do programmers have to memorize escape sequences and stuff? It would be helpful if there was a single page with all the reference tables in it.. I'll just bookmark 'em for now (;

  • jsieckman

    In the following example above:

    char chValue = '5'; // assigns 53 (ASCII code for '5')
    char chValue2 = 5; // assigns 5

    Does the bottom statement assign 5 or does it assign the character associated with the ASCII code for 5 (i.e. a club symbol)?


    • Alex

      The top statement assigns the character '5' (integer 53), which is printed as '5'.
      The bottom statement assigns in the integer value 5, which is printed as a club symbol in the Windows console.

  • PReinie

    Alex, thanks for the info!

    From my background I've used binary, octal, hex and decimal when referring to characters, so please make sure above when you say an 'a' is 97 you specify that it's (it is) a decimal 97. Granted the compiler assumes decimal, but readers may not.

    Also, "The following program asks the user to input a character, then prints out both the character and it’s ASCII code:" Please check in all the tutorials each use of "it's" which is short for "it is" and is never possessive. "its" is possessive just is his, hers and theirs are possessive and you do not use an apostrophe for them.

  • prabhakar

    respected ALEX, i have been deligently and sincerely trying to follow your "lessons".
    i tried to compile one code re. CHAR.

    [One word of caution: be careful not to mix up character (keyboard) numbers with actual numbers. The following two assignments are not the same

    view sourceprint?
    char chValue = '5'; // assigns 53 (ASCII code for '5')
    char chValue2 = 5; // assigns 5 ]

    What 'cout' gives me is

    a)5 for chValue
    b)a sign like "club in playing cards"

    please advise me---thanks prabhakar

    • Alex

      If you print char 53, you'll get the character '5'.
      If you print char 5, you'll get the "club in playing cards" on Windows, because the font that Windows uses in the console has this club symbol mapped to code point 5. Why? I guess Microsoft figured that putting a printable symbol at that code point was better than leaving something unprintable there.

      Note that this club symbol is not a standard part of ASCII and will not work on other operating systems, like Unix.

  • Bry

    Hi. Been having fun going through this tutorial. I was just compiling the ASCII code...

    It gave me a warning with visual c++ 2008 express until I changed the top line to...

    Thanks for creating this tutorial! :)

  • Vlad

    I tried declaring a variable as

    but it didn't work, how can i create a string variable

  • Shawn

    Ok, i tried the /v for form feed, which in my case could be represented as a new page(would feed lines until the text shown would be gone. But instead it read out as the male gender sign as a character. I just dont want to have to input like 15 /n's to make the same effect. I know an alternative is to make 15 /n's a char constant and just input it when i need a new page but im just wondering if im just doing something wrong. Help, please! :P

    • I've never tried using the form feed char. I doubt it works on a monitor, though it might still work in printers... maybe.

      You can't stick 15 /n's in a char because a char only holds one character, not 15. If you want 15 spaces, for now you'll have to do 15 cout << "\n"; until you learn how to do loops.

      • James

        I was just reading through the comments on this excellent tutorial.

        If you want to wipe the text off the terminal you can use the clear screen command, system("cls")

        Hope This is what you were lookign for! :)

        • Alex

          This solution will only work on some operating systems and is not recommended. system() makes a call to the operating system and runs the program "cls", which happens to clear the console on Windows. But it won't work on Unix, since Unix doesn't have an executable named cls.

  • Pathik

    Why do you need '/?'.... we can use question mark with cout....

    • Honestly, I don't know. :)

      • PReinie

        From my years of C coding, single quotes enclose one character and double-quotes enclose a string. Strings were (are?) far different than a char - mostly in storage (memory) and using them. Strings are one or more characters and terminated (usually with a zero - not the character 0, but all zero bits). Strings always take up more than 8 bits (one byte).
        cout may not care, but your variable declaration (compiler) may be particular about it and/or your code may not work.

        The slash question mark may be used in case a compiler interprets question marks as something else. This depends on your compiler, IE, it's just to make sure your code really does (compiles to) what you want it to do. Some pattern matching (MS Word?) use a question mark to substitute/match a single character, and to match a question mark you have to escape it. Same thing may be for some compilers.

  • Jeffey

    I made a program that makes a ASCII chart. Even though you can find this chart in almost any place dealing with coding. I thought it be fun to make my own reference.

    #include "stdafx.h"
    #include <iostream>

    int main()
    using namespace std;
    for(unsigned char nCount = 1; nCount <= 127; nCount++)
    if (nCount <= 127)
    cout << (int)nCount << " : " << nCount << endl;
    return 0;

    • Jeffey

      Oh! you may notice that nCount should be ucCount...thats because when I first wrote the program, it was an exercise that just counted up from 0. I just changed the int integer(int) to a char integer (unsigned char). Leaving the variable the same. Technicality there nothing wrong with that. However if you copy this program. I would suggest trying to use Hungarian Notion the correct way.

    • See ++

      Hi Jeffey. Nice idea to construct such a code. Actually you don't need to use the hypothetical statement if. I simplified your code:

Leave a Comment

Put all code inside code tags: [code]your code here[/code]