Integers are great for counting whole numbers, but sometimes we need to store very large numbers, or numbers with a fractional component. A floating point type variable is a variable that can hold a real number, such as 4.0, 2.5, 3.33, or 0.1226. There are three different floating point data types: float, double, and long double. A float is usually 4 bytes and a double 8 bytes, but these are not strict requirements, so sizes may vary. Long doubles were added to the language after it’s release for architectures that support even larger floating point numbers. But typically, they are also 8 bytes, equivalent to a double. Floating point data types are always signed (can hold positive and negative values).
Here are some declarations of floating point numbers:
float fValue; double dValue; long double dValue2;
The floating part of the name floating point refers to the fact that a floating point number can have a variable number of decimal places. For example, 2.5 has 1 decimal place, whereas 0.1226 has 4 decimal places.
When we assign numbers to floating point numbers, it is convention to use at least one decimal place. This helps distinguish floating point values from integer values.
int nValue = 5; // 5 means integer float fValue = 5.0; // 5.0 means floating point
How floating point variables store information is beyond the scope of this tutorial, but it is very similar to how numbers are written in scientific notation. Scientific notation is a useful shorthand for writing lengthy numbers in a concise manner. In scientific notation, a number has two parts: the significand, and a power of 10 called an exponent. The letter ‘e’ or ‘E’ is used to separate the two parts. Thus, a number such as 5e2 is equivalent to 5 * 10^2, or 500. The number 5e-2 is equivalent to 5 * 10^-2, or 0.05.
In fact, we can use scientific notation to assign values to floating point variables.
double dValue1 = 500.0; double dValue2 = 5e2; // another way to assign 500 double dValue3 = 0.05; double dValue4 = 5e-2; // another way to assign 0.05
Furthermore, if we output a number that is large enough, or has enough decimal places, it will be printed in scientific notation:
#include <iostream>
int main()
{
using namespace std;
double dValue = 1000000.0;
cout << dValue << endl;
dValue = 0.00001;
cout << dValue << endl;
return 0;
}
Outputs:
1e+006 1e-005
Precision
Consider the fraction 1/3. The decimal representation of this number is 0.33333333333333… with 3’s going out to infinity. An infinite length number would require infinite memory, and we typically only have 4 or 8 bytes. Floating point numbers can only store a certain number of digits, and the rest are lost. The precision of a floating point number is how many digits it can represent without information loss.
When outputting floating point numbers, cout has a default precision of 6 — that is, it assumes all variables are only significant to 6 digits, and hence it will truncate anything after that.
The following program shows cout truncating to 6 digits:
#include <iostream>
int main()
{
using namespace std;
float fValue;
fValue = 1.222222222222222f;
cout << fValue << endl;
fValue = 111.22222222222222f;
cout << fValue << endl;
fValue = 111111.222222222222f;
cout << fValue << endl;
}
This program outputs:
1.22222 111.222 111111
Note that each of these is only 6 digits.
However, we can override the default precision that cout shows by using the setprecision() function that is defined in a header file called iomanip.
#include <iostream>
#include <iomanip> // for setprecision()
int main()
{
using namespace std;
cout << setprecision(16); // show 16 digits
float fValue = 3.33333333333333333333333333333333333333f;
cout << fValue << endl;
double dValue = 3.3333333333333333333333333333333333333;
cout << dValue << endl;
Outputs:
3.333333253860474 3.333333333333334
Because we set the precision to 16 digits, each of the above numbers has 16 digits. But, as you can see, the numbers certainly aren’t precise to 16 digits!
Variables of type float typically have a precision of about 7 significant digits (which is why everything after that many digits in our answer above is junk). Variables of type double typically have a precision of about 16 significant digits. Variables of type double are named so because they offer approximately double the precision of a float.
Now let’s consider a really big number:
#include <iostream>
int main()
{
using namespace std;
float fValue = 123456789.0f;
cout << fValue << endl;
return 0;
}
Output:
1.23457e+008
1.23457e+008 is 1.23457 * 10^8, which is 123457000. Note that we have lost precision here too!
Consequently, one has to be careful when using floating point numbers that require more precision than the variables can hold.
Rounding errors
One of the reasons floating point numbers can be tricky is due to non-obvious differences between binary and decimal (base 10) numbers. In normal decimal numbers, the fraction 1/3rd is the infinite decimal sequence: 0.333333333… Similarly, consider the fraction 1/10. In decimal, this is easy represented as 0.1, and we are used to thinking of 0.1 as an easily representable number. However, in binary, 0.1 is represented by the infinite sequence: 0.00011001100110011…
You can see the effects of this in the following program:
#include <iomanip>
int main()
{
using namespace std;
cout << setprecision(17);
double dValue = 0.1;
cout << dValue << endl;
}
This outputs:
0.10000000000000001
Not quite 0.1! This is because the double had to truncate the approximation due to it’s limited memory, which resulted in a number that is not exactly 0.1. This is called a rounding error.
Rounding errors can play havoc with math-intense programs, as mathematical operations can compound the error. In the following program, we use 9 addition operations.
#include <iostream>
#include <iomanip>
int main()
{
using namespace std;
cout << setprecision(17);
double dValue;
dValue = 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1;
cout << dValue << endl;
}
This program should output 1, but it actually outputs:
0.99999999999999989
Note that the error is no longer in the last column like in the previous example! It has propagated to the second to last column. As you continue to do mathematical operations, this error can propagate further, causing the actual number to drift farther and farther from the number the user would expect.
Comparison of floating point numbers
One of the things that programmers like to do with numbers and variables is see whether two numbers or variables are equal to each other. C++ provides an operator called the equality operator (==) precisely for this purpose. For example, we could write a code snippet like this:
int x = 5; // integers have no precision issues
if (x==5)
cout << "x is 5" << endl;
else
cout << "x is not 5" << endl;
This program would print “x is 5″.
However, when using floating point numbers, you can get some unexpected results if the two numbers being compared are very close. Consider:
float fValue1 = 1.345f;
float fValue2 = 1.123f;
float fTotal = fValue1 + fValue2; // should be 2.468
if (fTotal == 2.468)
cout << "fTotal is 2.468";
else
cout << "fTotal is not 2.468";
This program prints:
fTotal is not 2.468
This result is due to rounding error. fTotal is actually being stored as 2.4679999, which is not 2.468!
For the same reason, the comparison operators >, >=, <, and <= may produce the wrong result when comparing two floating point numbers that are very close.
Conclusion
To summarize, the two things you should remember about floating point numbers:
1) Floating point numbers offer limited precision. Floats typically offer about 7 significant digits worth of precision, and doubles offer about 16 significant digits. Trying to use more significant digits will result in a loss of precision. (Note: placeholder zeros do not count as significant digits, so a number like 22,000,000,000, or 0.00000033 only counts for 2 digits).
2) Floating point numbers often have small rounding errors. Many times these go unnoticed because they are so small, and because the numbers are truncated for output before the error propagates into the part that is not truncated. Regardless, comparisons on floating point numbers may not give the expected results when two numbers are close.
The section on relational operators has more detail on comparing floating point numbers.
2.6 — Boolean Values
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Index
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2.4 — Integers
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2.6 — Boolean Values
Index
2.4 — Integers
wow………to be honest this was extremely confusing man…….
It is far less confusing after reading this. Thank you. In class we covered this in about ten minutes and moved on to the next thing.
I’ve been to a few sites already trying to get a grasp on these (floats/doubles) and this summation really did the trick.
Thanks!
What do the f’s after some of the float and double values mean?
By default, if you type a floating point value into C++ it’s typed as a double. Consequently, if you do something like this:
You’re assigning a double to a float, which loses precision, and the compiler will probably complain.
Putting an “f” after the value means that you intend that value to be a float, not a double. Then when you do this:
You’re assigning a float value to a float variable, which makes more sense.
Is there something wrong with my code?
The compiler brings up a problem with setprecision()..
Thanks
You need to include iomanip.h to use setprecision() that way.
See the lesson on ostream for more info about output manipulators and stuff.
/* Program to know real value of fTotal */
#include <iostream.h>
#include <conio.h>
void main()
{
clrscr();
double fValue;
float fValue1 = 1.345f;
float fValue2 = 1.123f;
float fTotal = fValue1 + fValue2; // should be 2.468
if (fTotal == 2.468)
{
cout << "n fTotal is 2.468";
}
else
{
cout << "n fTotal is not 2.468";
}
printf("n The real value of fTotal is %0.7f", fTotal);
getch();
}
/* End of Pgram */
/* Program to know real value of fTotal */
#include <iostream.h>
#include <conio.h>
void main()
{
clrscr();
float fValue1 = 1.345f;
float fValue2 = 1.123f;
float fTotal = fValue1 + fValue2; // should be 2.468
if (fTotal == 2.468)
{
cout << "n fTotal is 2.468";
}
else
{
cout << "n fTotal is not 2.468";
}
printf("n The real value of fTotal is %0.7f", fTotal);
getch();
}
/* End of Pgram */
Coming form a Java background, I wonder if anyone can advise me a C++ library with a similar function as Java’s BigDecimal.
Preferably one that works on Linux with gcc(so not the decimal type from Visual C++)
So with all the rounding errors and precision problems, how do programmers deal with operations that need to display something that would end up with a precision or rounding error? Or am I just over-thinking things?
Most of the time it’s simply not necessary to display a number to the number of significant digits where precision/rounding errors creep in. Generally with floating point numbers, programs will truncate the display to 2-5 decimals.
This could also be some reading, if interested.
http://babbage.cs.qc.edu/courses/cs341/IEEE-754references.html
And, “What Every Computer Scientist Should Know About Floating-Point Arithmetic”:
http://www.validlab.com/goldberg/paper.pdf
this is very help full site
how can i make the value a user inputs into a float?
#include <iostream> using namespace std; int divide() { cout << "Please enter 2 numbers" << endl; cout << "dividend \t: " ; float x; cin >> x; cout << "divisor \t: " ; float y; cin >> y; return x / y; }then when i run the program from main() and i put in 2 values like eg. x = 10 y = 3 then the answer is 3 instead of 3.333333
You are already storing the user input values as a flow. The problem is that your function is returning an integer, so it’s truncating the result of x/y. Change your function to return a float and you will be good.
I set the precision level to 4, and added cout for the 2 values, fValue1 + fValue2.
I got fValue1 IS actually rounded off to 1.345 and fValue2 IS actually 1.123, expecting now the get the result of 2.468, but still reports ‘fTotal is not 2.468′
Why is that?
Chris
Rounding error. The numbers printed on your screen by cout are rounded in this case, so you’re not seeing the full representation. However, when you do the comparison, it does so with the actual numbers, not the rounded ones, which can lead to rounding issues.
How do I convert a Float say
x = 1234.567890123456789
to
y = 1234.5678901234 (small float ..10 decimal places only)
Something similar to setPrecision, to use NOT for display/Printing, but to use as a value for calculations / pass it on to a Database etc ?
I’m not sure what the best way to do this is. For small numbers, you can multiply by 10^x, cast to an integer to drop the remaining decimals, then divide by 10^x. However, if your number is too large you’ll overflow the int when you do the casting so I won’t say this is foolproof.
Didn’t understand how 0.1 is represented in binary by 0.00011001100110011…
In decimal, .1 is tenths, .01 is hundredths, .001 is thousandths and so on. Likewise, in binary, .1 is halves, .01 is quarters, .001 is eights, and so on.
0.000110011… would be equal to 1/16 + 1/32 + 1/256 + 1/512 + …
why does the float work.its a simple program to calculate the area of a triangle.but if i put the value of base as 3 and height as 3 ,i get the result as 4 instead of 4.5.here is the code.i don’t get the answer in decimal
#include "stdafx.h" #include #include "add.h" #include int main() { using namespace std; cout <> b; cout <>h; float a=divide(multiply(b,h),2); //area of triangle is half into base into height cout << "area of triangle :" << a <<endl; }When I run the following code, the values seem really wrong when output. What is going wrong here?
#include <iostream> #include <iomanip> // for setprecision() int main() { using namespace std; cout << setprecision(6) << "nprecision 6n"; float fValue; fValue = 1.22222222222222222f; cout << fValue << endl; fValue = 111111111.222222222f; cout << fValue << endl; cout << setprecision(16) << "nprecision 16n"; fValue = 1.22222222222222222f; cout << fValue << endl; fValue = 111111111.222222222f; cout << fValue << endl; return 0; }your C ++ compiler has a tendency to roundoff 8th precision onwards.
For any value lesser then 8;
It will display 1 lesser than called for.
In the code example right after “rounding errors,” why is there no “#include ” when there is a cout later and also “using namespace std”? Is it a miss type or is there a reason…?
Sorry after include it is suppsed to say io stream in angled brackets
# include <iostream> using namespace std; int main() { int intVar = 1500000000; intVar = (intVar * 10) / 10; cout << "intVar :" << intVar << endl; intVar = 1500000000; intVar = (static_cast<double>(intVar) * 10) / 10; cout << "intVar :" << intVar << endl; system("pause"); return 0; } /*devc++ 4.9.9.2 compiler instead of printing error value is displaying assigned value directly in the first instance.where am I going wrong OR is the new DEV C++ compiler which is the responsible for this... */Guess all authors are prone to typo errors.
hi there, can you give me an example of addition with no outputs?
I’m confused by your use of the term ‘real number’.
In mathematics a real number is any number which isn’t an imaginary number, which means that both C++ integer and floating-point data-types can hold real numbers, and the only difference between them is that floating-point data-types can represent decimal fractions, as opposed to integer data-types which can only hold natural numbers (aka counting numbers, or whole numbers).
Also – a general stylistic point – you’ve often used “it’s” where “its” is the correct word to use, cf. http://www.buckingham.ac.uk/english/guide/its.html.