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9.14 — Dynamically allocating arrays

In addition to dynamically allocating single values, we can also dynamically allocate arrays of variables. Unlike a fixed array, where the array size must be fixed at compile time, dynamically allocating an array allows us to choose an array length at runtime.

To allocate an array dynamically, we use the array form of new and delete (often called new[] and delete[]):

Because we are allocating an array, C++ knows that it should use the array version of new instead of the scalar version of new. Essentially, the new[] operator is called, even though the [] isn’t placed next to the new keyword.

The length of dynamically allocated arrays has to be a type that’s convertible to std::size_t. We could use int, but that would cause a compiler warning when the compiler is configured with a high warning level. We have the choice between using std::size_t as the type of length, or declaring length as an int and then casting it when we create the array like so:

Note that because this memory is allocated from a different place than the memory used for fixed arrays, the size of the array can be quite large. You can run the program above and allocate an array of length 1,000,000 (or probably even 100,000,000) without issue. Try it! Because of this, programs that need to allocate a lot of memory in C++ typically do so dynamically.

Dynamically deleting arrays

When deleting a dynamically allocated array, we have to use the array version of delete, which is delete[].

This tells the CPU that it needs to clean up multiple variables instead of a single variable. One of the most common mistakes that new programmers make when dealing with dynamic memory allocation is to use delete instead of delete[] when deleting a dynamically allocated array. Using the scalar version of delete on an array will result in undefined behavior, such as data corruption, memory leaks, crashes, or other problems.

One often asked question of array delete[] is, “How does array delete know how much memory to delete?” The answer is that array new[] keeps track of how much memory was allocated to a variable, so that array delete[] can delete the proper amount. Unfortunately, this size/length isn’t accessible to the programmer.

Dynamic arrays are almost identical to fixed arrays

In lesson 9.10 -- Pointers and arrays, you learned that a fixed array holds the memory address of the first array element. You also learned that a fixed array can decay into a pointer that points to the first element of the array. In this decayed form, the length of the fixed array is not available (and therefore neither is the size of the array via sizeof()), but otherwise there is little difference.

A dynamic array starts its life as a pointer that points to the first element of the array. Consequently, it has the same limitations in that it doesn’t know its length or size. A dynamic array functions identically to a decayed fixed array, with the exception that the programmer is responsible for deallocating the dynamic array via the delete[] keyword.

Initializing dynamically allocated arrays

If you want to initialize a dynamically allocated array to 0, the syntax is quite simple:

Prior to C++11, there was no easy way to initialize a dynamic array to a non-zero value (initializer lists only worked for fixed arrays). This means you had to loop through the array and assign element values explicitly.

Super annoying!

However, starting with C++11, it’s now possible to initialize dynamic arrays using initializer lists!

Note that this syntax has no operator= between the array length and the initializer list.

For consistency, fixed arrays can also be initialized using uniform initialization:

Explicitly stating the size of the array is optional. Doing so can help catching errors early, because the compiler will warn you when the specified length is less than the actual length.

As of the time of writing, the GCC still has a bug where initializing a dynamically allocated array of chars using a C-style string literal causes a compiler error:

If you have a need to do this on GCC, dynamically allocate a std::string instead (or allocate your char array and then copy the string in).

Resizing arrays

Dynamically allocating an array allows you to set the array length at the time of allocation. However, C++ does not provide a built-in way to resize an array that has already been allocated. It is possible to work around this limitation by dynamically allocating a new array, copying the elements over, and deleting the old array. However, this is error prone, especially when the element type is a class (which have special rules governing how they are created).

Consequently, we recommend avoiding doing this yourself.

Fortunately, if you need this capability, C++ provides a resizable array as part of the standard library called std::vector. We’ll introduce std::vector shortly.

Quiz time


Question #1

Write a program that:
* Asks the user how many names they wish to enter.
* Dynamically allocates a std::string array.
* Asks the user to enter each name.
* Calls std::sort to sort the names (See 9.4 -- Sorting an array using selection sort and 9.11 -- Pointer arithmetic and array indexing)
* Prints the sorted list of names.

std::string supports comparing strings via the comparison operators < and >. You don’t need to implement string comparison by hand.

Your output should match this:

How many names would you like to enter? 5
Enter name #1: Jason
Enter name #2: Mark
Enter name #3: Alex
Enter name #4: Chris
Enter name #5: John

Here is your sorted list:
Name #1: Alex
Name #2: Chris
Name #3: Jason
Name #4: John
Name #5: Mark

A reminder

You can use std::getline() to read in names that contain spaces.

A reminder

To use std::sort() with a pointer to an array, calculate begin and end manually

Show Solution


9.15 -- Pointers and const
Index
9.13 -- Dynamic memory allocation with new and delete

732 comments to 9.14 — Dynamically allocating arrays

  • Jurbit

    If we were to omit the * next to auto would that change anything, or does auto know that names is a pointer because it's being initialized with new?

    I was able to run it and compile the program without the * but I wasn't sure what that does under the hood.

    Thanks

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