In mathematics, an operation is a mathematical calculation involving zero or more input values (called operands) that produces an output value. Common operations (such as addition) use special symbols (such as +) that denote the operation. These symbols are called operators. Operators in programming work the same way except the names may not always be a symbol. Operators work analogously to functions that take input parameters and return a value, except they are more concise. For example, 4 + 2 * 3 is much easier to read than add(4, mult(2, 3))!
In order to properly evaluate an expression such as
4 + 2 * 3, we must understand both what the operators do, and the correct order to apply them. The order in which operators are evaluated in a compound expression is called operator precedence. Using normal mathematical precedence rules (which state that multiplication is resolved before addition), we know that the above expression should evaluate as
4 + (2 * 3) to produce the value 10.
In C++, when the compiler encounters an expression, it must similarly analyze the expression and determine how it should be evaluated. To assist with this, all operators are assigned a level of precedence. Those with the highest precedence are evaluated first. You can see in the table below that multiplication and division (precedence level 5) have a higher precedence than addition and subtraction (precedence level 6). The compiler uses these levels to determine how to evaluate expressions it encounters.
Thus, 4 + 2 * 3 evaluates as 4 + (2 * 3) because multiplication has a higher level of precedence than addition.
If two operators with the same precedence level are adjacent to each other in an expression, the operator associativity rules tell the compiler whether to evaluate the operators from left to right or from right to left. For example, in the expression
3 * 4 / 2, the multiplication and division operators are both precedence level 5. Level 5 has an associativity of left to right, so the expression is resolved from left to right:
(3 * 4) / 2 = 6.
Table of operators
- Precedence level 1 is the highest precedence level, and level 17 is the lowest. Operators with a higher precedence level get evaluated first.
- L->R means left to right associativity.
- R->L means right to left associativity.
Global scope (unary)
Class scope (binary)
Uniform initialization (C++11)
Functional cast (C++11)
Member access from object
Member access from object ptr
Run-time type information
Cast away const
Run-time type-checked cast
Cast one type to another
Compile-time type-checked cast
typeid(type) or typeid(expression)
Size in bytes
Dynamic memory allocation
Dynamic array allocation
Dynamic memory deletion
Dynamic array deletion
sizeof(type) or sizeof(expression)
Member pointer selector
Member object selector
expression * expression
expression / expression
expression % expression
expression + expression
expression - expression
Bitwise shift left
Bitwise shift right
expression << expression
expression >> expression
Comparison less than
Comparison less than or equals
Comparison greater than
Comparison greater than or equals
expression < expression
expression <= expression
expression > expression
expression >= expression
expression == expression
expression != expression
|10 L->R||&||Bitwise AND||expression & expression|
|11 L->R||^||Bitwise XOR||expression ^ expression|
|12 L->R|||||Bitwise OR||expression | expression|
|13 L->R||&&||Logical AND||expression && expression|
|14 L->R||||||Logical OR||expression || expression|
Conditional (see note below)
Bitwise shift left assignment
Bitwise shift right assignment
Bitwise AND assignment
Bitwise OR assignment
Bitwise XOR assignment
expression ? expression : expression
lvalue = expression
lvalue *= expression
lvalue /= expression
lvalue %= expression
lvalue += expression
lvalue -= expression
lvalue <<= expression
lvalue >>= expression
lvalue &= expression
lvalue |= expression
lvalue ^= expression
|16 R->L||throw||Throw expression||throw expression|
|17 L->R||,||Comma operator||expression, expression|
Note: The expression in the middle of the conditional operator ?: is evaluated as if it were parenthesized.
A few operators you should already recognize: +, -, *, /, (), <, and >. These arithmetic and relational operators have the same meaning in C++ as they do in every-day usage.
However, unless you have experience with another programming language, it’s likely the majority of the operators in this table will be incomprehensible to you right now. That’s expected at this point. We’ll cover many of them in this chapter, and the rest will be introduced as there is a need for them.
The above table is primarily meant to be a reference chart that you can refer back to in the future to resolve any precedence or associativity questions you have.
That said, if you have an expression that uses operators of different types, it is a best practice to use parenthesis to explicitly disambiguate the order of evaluation.
Rule: If your expression uses different operators, use parenthesis to make it clear how the expression should evaluate, even if they are technically unnecessary.
How do I do exponents?
C++ doesn’t include an exponentiation operator. We discuss alternatives in lesson 3.2 -- Arithmetic operators .
1) You know from everyday mathematics that expressions inside of parentheses get evaluated first. For example, in the expression
(2 + 3) * 4, the
(2 + 3) part is evaluated first.
For this exercise, you are given a set of expressions that have no parentheses. Using the operator precedence and associativity rules in the table above, add parentheses to each expression to make it clear how the compiler will evaluate the expression.
Hint: Use the pattern column in the table above to determine whether the operator is unary (has one operand) or binary (has two operands). Review section 1.5 -- A first look at operators  if you need a refresher on what unary and binary operators are.
Sample problem: x = 2 + 3 % 4
Binary operator % has higher precedence than operator + or operator =, so it gets evaluated first:
x = 2 + (3 % 4)
Binary operator + has a higher precedence than operator =, so it gets evaluated next:
Final answer: x = (2 + (3 % 4))
We now no longer need the table above to understand how this expression will evaluate.
a) x = 3 + 4 + 5;
b) x = y = z;
c) z *= ++y + 5;
d) a || b && c || d;
1) Show Solution 
|3.2 -- Arithmetic operators |
|2.10 -- Chapter 2 comprehensive quiz |