8.5a — Constructor member initializer lists

In the previous lesson, for simplicity, we initialized our class member data in the constructor using the assignment operator. For example:

When the class’s constructor is executed, m_value1, m_value2, and m_value3 are created. Then the body of the constructor is run, where the member data variables are assigned values. This is similar to the flow of the following code in non-object-oriented C++:

While this is valid within the syntax of the C++ language, it does not exhibit good style (and may be less efficient than initialization).

However, as you have learned in previous lessons, some types of data (e.g. const and reference variables) must be initialized on the line they are declared. Consider the following example:

This produces code similar to the following:

Assigning values to const or reference member variables in the body of the constructor is clearly not sufficient in some cases.

Member initializer lists

To solve this problem, C++ provides a method for initializing class member variables (rather than assigning values to them after they are created) via a member initializer list (often called a “member initialization list”). Do not confuse these with the similarly named initializer list that we can use to assign values to arrays.

In lesson 2.1 -- Fundamental variable definition, initialization, and assignment, you learned that you could initialize variables in three ways: copy, direct, and via uniform initialization (C++11 only).

Using an initialization list is almost identical to doing direct initialization (or uniform initialization in C++11).

This is something that is best learned by example. Revisiting our code that does assignments in the constructor body:

Now let’s write the same code using an initialization list:

This prints:

Something(1, 2.2, c)

The member initializer list is inserted after the constructor parameters. It begins with a colon (:), and then lists each variable to initialize along with the value for that variable separated by a comma.

Note that we no longer need to do the assignments in the constructor body, since the initializer list replaces that functionality. Also note that the initializer list does not end in a semicolon.

Of course, constructors are more useful when we allow the caller to pass in the initialization values:

This prints:

Something(1, 2.2, c)

Note that you can use default parameters to provide a default value in case the user didn’t pass one in.

Here’s an example of a class that has a const member variable:

This works because we’re allowed to initialize const variables (but not assign to them!).

Rule: Use member initializer lists to initialize your class member variables instead of assignment.

Uniform initialization in C++11

In C++11, instead of direct initialization, uniform initialization can be used:

We strongly encourage you to begin using this new syntax (even if you aren’t using const or reference member variables) as initialization lists are required when doing composition and inheritance (subjects we will be covering shortly).

Rule: Favor uniform initialization over direct initialization if you compiler is C++11 compatible

Initializing array members with member initializer lists

Consider a class with an array member:

Prior to C++11, you can only zero an array member via a member initialization list:

However, in C++11, you can fully initialize a member array using uniform initialization:

Initializing member variables that are classes

A member initialization list can also be used to initialize members that are classes.

This prints:

A 4
B 5

When variable b is constructed, the B(int) constructor is called with value 5. Before the body of the constructor executes, m_a is initialized, calling the A(int) constructor with value 4. This prints “A 4”. Then control returns back to the B constructor, and the body of the B constructor executes, printing “B 5”.

Formatting your initializer lists

C++ gives you a lot of flexibility in how to format your initializer lists, and it’s really up to you how you’d like to proceed. But here are some recommendations:

If the initializer list fits on the same line as the function name, then it’s fine to put everything on one line:

If the initializer list doesn’t fit on the same line as the function name, then it should go indented on the next line.

If all of the initializers don’t fit on a single line (or the initializers are non-trivial), then you can space them out, one per line:


Member initializer lists allow us to initialize our members rather than assign values to them. This is the only way to initialize members that require values upon initialization, such as const or reference members, and it can be more performant than assigning values in the body of the constructor. Member initializer lists work both with fundamental types and members that are classes themselves.

Quiz Time

1) Write a class named RGBA that contains 4 member variables of type std::uint8_t named m_red, m_green, m_blue, and m_alpha (#include cstdint to access type std::uint8_t). Assign default values of 0 to m_red, m_green, and m_blue, and 255 to m_alpha. Create a constructor that uses a member initializer list that allows the user to initialize values for m_red, m_blue, m_green, and m_alpha. Include a print() function that outputs the value of the member variables.

If you need a reminder about how to use the fixed width integers, please review lesson 2.4a -- Fixed-width integers and the unsigned controversy.

Hint: If your print() function isn’t working correctly, make sure you’re casting uint8_t to an int.

The following code should run:

and produce the result:

r=0 g=127 b=127 a=255

Show Solution

8.5b -- Non-static member initialization
8.5 -- Constructors

109 comments to 8.5a — Constructor member initializer lists

  • Shamlei

    Hey it just keeps getting more and more interesting and powerfull and you seem to be able to keep the same high quality of explanations.

    With all of this learned on constructors does that mean a class should only ever have one constructor ?

    Default values and initializer lists seem to make it possible for most cases.


  • Hardik

    Hi Alex,
    In The Given Code :-

    How Can We Instantiate an object of Class A on Line-12 if the default constructor isn’t provided in Class A?
    Reply Please 🙂

    • Alex

      We don’t ever create an object of type A without a parameter, so a default constructor isn’t needed.

      B b(5) instantiates an object of type B, which allocates memory for B, including the member m_a of type A. B’s constructor is then executed with parameter 5, and the variable m_a is initialized using the A(int) constructor to the value of 4.

      Remember, classes are just type definitions. They do not actually allocate memory until an object of the class is instantiated.

      • Hardik

        I think you got me wrong !
        Let Me Start Again.
        We know that compilation starts from the start of the program.Yes? Ok, So When It Encounters Class A it doesnt allocate any memory for it as we know that it is just a type definition. Then It Goes to Class B and there it encounters A m_a but then, Shouldn’t it flag it as an error as there is no default constructor provided in Class A?

        • Alex

          No, because a default constructor for A is never called. We only ever initialize A with an integer parameter, so we only need a constructor that can handle an int.

          • Hardik

            It is called on LINE 12, No?

            • Alex

              No. Line 12 just tells the compiler that B contains an A member named m_a. Initialization is handled via the constructors.

            • Hardik

              So, Why does this print "A"?
              Shouldn’t it just "tell" the compiler that B contains A member name m_a?

              • Alex

                If you don’t explicitly tell the compiler how to initialize a member that is itself a class, the compiler will default to using the default constructor.

                In this case, the B constructor doesn’t initialize m_a, so the compiler uses the default constructor for A to initialize m_a.

                • Hardik

                  Just Like That, In The 1st Case We Haven’t told the compiler how to initialize member m_a till Line 14. So Why it doesn’t flag that line 12 as an error?

                • Alex

                  Because it’s just part of the type definition, it doesn’t actually instantiate anything, so there’s no need to specify how the variable is initialized at that point.

  • Curiosity

    Look, we all know that a variable can only be created once.Yes?
    So, In The Section : "Member Initialization Lists", How can we create a single member variable twice;
    1st, When we create it.
    Example :-

    2nd, When we initialize it using member initialization lists(initialization involves CREATION too !)
    Example :-

    I hope you have understood my question 🙂

    • Alex

      Three things:

      1) This is a variable definition:

      2) This is a variable initialization:

      3) This is the variable instantiation:

      When we instantiate variable s (of type Something), the member m_value is created. It is then initialized by the constructor.

      • Curiosity

        That’s what i’m asking bro !
        When Vairiable m_value is created for the 1st time, How Can it be initialized (which involves creation too !) ?
        The following isn’t valid, No?

        • Alex

          No, that’s not valid, as it’s a redefinition of x.

          When you type “int x = 5”, variable x is first given a memory location, and then it is initialized to 5.

          With classes, when you instantiate an object, the object is first given a memory location, and then the constructor is called to initialize the object.

          With fundamental variables, the definition and initialization are done in the same line. With classes, the definition and initialization are defined on separate lines. This was done so that different constructors can initialize members in different ways, depending on which constructor was called.

          • Curiosity

            So, It Means Re-Creation is allowed in the case of classes !

            • Alex

              I don’t know what “re-creation” means in this case. As I said, the difference is that in classes, the definition and initialization happen in separate places. The compiler handles the details. There’s no redefinitions here.

              • Curiosity

                It means things "like" these is allowed in the case of classes :-

                note:- I have said "LIKE".

                • Alex

                  I get what you’re thinking here, but I think that’s a bit misleading. In the int case, the top line actually instantiates an integer. In the class case, defining an int member doesn’t actually instantiate an int.

                • Curiosity

                  See, but when we declare an object of this class, A specific amt. Of memory is instanitiated for that object. And Now, Memory is allocated for members also !
                  Now My question arrives, How is member m_x is defined 2 times(1st - Definition(Eg - int x;) & 2nd initialization(involves definition too(Eg - int x = 5;) or is definition and initialization done in different places in classes?

                • Alex

                  That’s what I’ve been telling you -- definition and initialization usually happen separately in classes.

                • Hardik

                  Can you tell me the reason why it is so different in classes?

                • Alex

                  So that different constructors can initialize the members in different ways if desired. If you had to initialize the variables right where they were defined, then constructors wouldn’t be near as useful.

  • Chris

    Due to the wording in your quiz, I interpreted the question in a different way than your solution provided.  The first part was simple enough, if RGBA were instantiated with no arguments, then RGBA members will be initialized to 0,0,0,255

    The second part says if the user passes red, green, blue and optionally alpha, then initialize the members accordingly.  Due to the fact that ‘optionally’ is used on only alpha, that tells me that all three color components must be provided.  Your solution would allow only red or only red and blue components to be provided.

    My solution according to my own interpretation of the question uses these two constructors.

    Also want to thank you for taking the time to provide these tutorials.

  • Felipe

    Isn’t this code format better, for the last question of the quiz?

  • George

    Hi Alex! Very nice site, thank you so much!

    I would appreciate it if you would help me to solve this.

    If we have the following class:

    And the following main function:

    Is this correct:
    1) the constructor for the object y is called (***)
    2) the constructor for the object _y is called (///)
    3) the assignment operator is called (###)

    Thanks in advance!

    • Alex

      (***) and (###) are correct. The constructor for _y is actually called here:

      After the function parameters are assigned, but before the body of the constructor executes.

      This makes sense since the definition of Yyy _y is just a definition, it’s not executable code.

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